Amir Khan Reveals Surprising Pick for Joshua-Wilder Clash: "He's Got the Edge"

Ronald Crawley May 7, 2025, 4:11 a.m.
None

Anthony Joshua and Deontay Wilder might face each other in the ring, and Amir Khan thinks Joshua will come out on top.

Both heavyweights have had ups and downs lately. Joshua, a former two-time world champion, lost his belts to Oleksandr Usyk twice in 2021 and 2022. He also got stopped by Daniel Dubois in September. But he's got big wins under his belt too. He beat Wladimir Klitschko, Kubrat Pulev, and Dillian Whyte. And let's not forget how he bounced back after losing to Andy Ruiz Jr, winning the rematch six months later.

Wilder, who used to hold the WBC title, has had a tough time lately. He's lost four of his last five fights. Tyson Fury beat him twice, and he's also lost to Joseph Parker and Zhilei Zhang. But he's not giving up. He's getting back in the ring in June, taking on Tyrrell Herndon in Kansas.

So, who'd win if these two met? Amir Khan thinks he knows. In a game of winner stays on with Mail Sport Boxing, Khan said:

"Leaning more towards Joshua, so I think Joshua on that one."

You can watch Khan make his prediction in this Mail Sport Boxing YouTube video.

But don't get too excited just yet. This fight's not happening anytime soon. Joshua's about to have elbow surgery, so he'll be out of action for a while. And that hoped-for match with Tyson Fury? It's probably not happening either, now that Fury's retired after losing twice to Usyk.

So, we'll have to wait and see what happens next for these heavyweight stars. Will Joshua recover well from his surgery? Can Wilder get back to his winning ways? Only time will tell.

Share

Comments

var _paq = window._paq = window._paq || []; _paq.push(['trackPageView']); _paq.push(['enableLinkTracking']); (function() { var u="//mm.magnet.kiev.ua/"; _paq.push(['setTrackerUrl', u+'matomo.php']); _paq.push(['setSiteId', '1']); var d=document, g=d.createElement('script'), s=d.getElementsByTagName('script')[0]; g.async=true; g.src=u+'matomo.js'; s.parentNode.insertBefore(g,s); })();