Anthony Joshua Reveals Unexpected Next Target After Fury Retirement: "It's Personal Now"

George Fields Jan. 31, 2025, 7:10 a.m.
None

Anthony Joshua is getting ready for one last shot at heavyweight glory. The British boxer has been a big name in the sport for 13 years, bringing in lots of fans and helping to make heavyweight boxing popular again.

Joshua's career has seen plenty of ups and downs. He quickly became a world champion after turning pro, beating big names like Wladimir Klitschko, Dillian Whyte, and Aleksandr Povetkin. But he's had some tough losses too. Andy Ruiz shocked everyone by beating him, and then Oleksandr Usyk beat him twice in a row, taking away all his belts.

His most recent fight didn't go well either. Daniel Dubois knocked him out in the 5th round back in September. After that, everyone thought Joshua would fight Tyson Fury next, since they'd both lost to Usyk. But those plans fell through when Fury announced he was retiring in January.

So what's next for Joshua? His promoter, Eddie Hearn, told talkSPORT Boxing about their plans:

"We're not looking at a rematch with Daniel Dubois. We're looking at fighting for the world heavyweight championship and becoming a three-time heavyweight world champion."

Hearn thinks Joseph Parker will beat Dubois when they fight for the IBF title on February 22. If that happens, Parker could be Joshua's next opponent.

Derek Chisora, who's fought Parker before, doesn't agree. He's backing Dubois to keep his title. But Hearn is confident Parker will pull off an upset.

Joshua's got one more chance to become champion again. It's been a long road, but he's not giving up yet.

Share

Comments

var _paq = window._paq = window._paq || []; _paq.push(['trackPageView']); _paq.push(['enableLinkTracking']); (function() { var u="//mm.magnet.kiev.ua/"; _paq.push(['setTrackerUrl', u+'matomo.php']); _paq.push(['setSiteId', '1']); var d=document, g=d.createElement('script'), s=d.getElementsByTagName('script')[0]; g.async=true; g.src=u+'matomo.js'; s.parentNode.insertBefore(g,s); })();