Yang assessed Tsarukyan's chances of winning the UFC title

Dmitriy Kel April 2, 2024, 5:40 p.m.

Former UFC lightweight champion Petr Yan believes that Arman Tsarukyan is capable of becoming the promotion's lightweight champion.

The Armenian will face Brazilian Charles Oliveira on April 13 at UFC 300 in Las Vegas.

"I think Arman can become a UFC champion. He has everything - skills, ambition, and his age allows. The question is when it will happen. People also become champions at 35 when no one believed it could happen. If Arman stays in the same focus, with the same attitude, will believe in his dream, his goal, visualize it and bring it closer, then everything is real," said Yan in an interview with MMA Fighting YouTube channel.

Watch this story: What time is UFC 309 Tonight? Oliveira vs Chandler - Start times, Schedules, Fight Card

UFC Fight Night 248 tournament results

Here are the results from UFC Fight Night 248, which took place on November 23 ...

UFC Fight Night 248: watch online, streaming links

On November 23, Macau will host UFC Fight Night 248. The broadcast of the preliminary ...

UFC Fight Night 248 weigh-in results

Here are the results of the weigh-ins for UFC Fight Night 248, which takes place ...

Figueredo: "I want to knock out Jan."

Former UFC flyweight champion Deiveson Figueredo has spoken out about his fight with former ...

Jones named a stipulation for the fight with Aspinall

UFC heavyweight champion Jon Jones has stated that he will only accept a fight ...

UFC 309. Jones vs. Miocic: watch online, broadcast links

On the night of November 17, the UFC 309 tournament will take place in New ...

Comments

var _paq = window._paq = window._paq || []; _paq.push(['trackPageView']); _paq.push(['enableLinkTracking']); (function() { var u="//mm.magnet.kiev.ua/"; _paq.push(['setTrackerUrl', u+'matomo.php']); _paq.push(['setSiteId', '1']); var d=document, g=d.createElement('script'), s=d.getElementsByTagName('script')[0]; g.async=true; g.src=u+'matomo.js'; s.parentNode.insertBefore(g,s); })();